Re: caculating the center of the sphere
- From: klewis@xxxxxxxxxxxxxxxx (Keith A. Lewis)
- Date: Thu, 30 Mar 2006 23:58:18 +0000 (UTC)
"sal028" <shirinlakhani@xxxxxxxxx> writes in article <1143742963.526334.259030@xxxxxxxxxxxxxxxxxxxxxxxxxxxx> dated 30 Mar 2006 10:22:43 -0800:
I want to find the center of a sphere with radius R and the coordinates
of the point on the sphere are (x,y,z) How can I calculate the center
with this information
You need 4 points on the surface of the sphere which do not all lie in a
single plane.
The center of the sphere is equidistant from all 4 points. Choose any 2
points and there is a plane between them which is the set of equidistant
points. Any 3 of these planes intersect in a single point, which is the
center of the sphere.
--Keith Lewis klewis {at} mitre.org
The above may not (yet) represent the opinions of my employer.
.
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- From: sal028
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