Re: a question about algebraic numbers
- From: quasi <quasi@xxxxxxxx>
- Date: Sun, 02 Apr 2006 18:46:36 -0400
On Sun, 02 Apr 2006 18:28:17 -0400, quasi <quasi@xxxxxxxx> wrote:
On Sun, 02 Apr 2006 18:00:34 EDT, Feng <lux@xxxxxxxxxxxx> wrote:
From others's post, I am considering a question, if a and b in C (complex numbers)are both algebraic, then what can we know about ab?ab is also algebraic, that is obvious, anything else?
for example, is there any bound of the degree?
deg(ab) <= deg(a)*deg(b)
The degree of the product is bounded above by the product of the
degrees of the factors.
The proof is immediate -- just consider the chain of fields Q < Q(a) <
Q(a,b).
Less immediate, but true, is the following:
Theorem:
Let a,b be algebraic, and let m=deg(a), n=deg(b).
If (m,n)=1 then deg(a+b)=m*n.
I don't recall the proof, but I remember that it used some Galois
theory.
Is the same result true for the product?
Question:
Let a,b be algebraic, and let m=deg(a), n=deg(b).
If (m,n)=1 must deg(a*b)=m*n?
quasi
.
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