Re: Fibonacci and the roullette wheel


D. Akers wrote:
Alexander wrote:
<snip>"Since the bets would be placed on each of the block bets, thus
covering every number other then the 0 or double 0, you would require a
long sequence of results landing on 0 or double 0 to prevent a profit."
<snip>
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Re:
I didn't comprehend this in my first read of your post. If you cover
every number but 0 and 00 by betting all three blocks of 12, then the
probability of losing all three wagers (0 or 00) on any given spin is
5.26% on a double-0 wheel. Unless I'm missing something in your system,
any other result (1 through 36) is a wash since any win comes with two
loses. I would suggest you run your system on just one block of 12.

It's not quite a wash, since the amount bet on a particular spin in
each of the three blocks would depend on the history of that block.
Ignoring the 0 - 00 trap, on every spin, one of the bets would be the
start of the Fib series, since in that block, there was a win on the
previous spin...

But of course, there is *no* way to combine losing bets of various
sizes to create a winning situation in the long run...

.

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