Re: Old chestnut: f(f(x))=exp(x)



The problem of finding a solution to f(f(x)) = exp(x) has come up in
this newsgroup before. I've suggested a possible solution which I
believe will be the "best and most natural" solution, if we can prove
that the Taylor series for the solution of f(f(x)) = exp(x)-1 has a
non-zero radius of convergence.

http://groups.google.com/group/sci.math/msg/3c85c5acfbd2ee49?hl=en&;

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