Re: continuous function



In news:<1148361625.233423.300920@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>
schrieb Proginoskes <CCHeckman@xxxxxxxxx>:
Robert Israel wrote:
Jonas <asdf@xxxxxxxxxxxxxxx> wrote:
let f:RxR->R
where R is the real numbers
let g:R->R be an arbitrary bijective continous function.
if fog (the composition of f and g) is alsways continuous for all g's ( that
is for all bijective continuous functions), is f then continuous?

Hint: Try the most obvious g.

Of course, that only works with the standard topology.

???

It works whenever there are identical topologies on domain and range of g.

If not, the result is only true
if the topologies are homeomorphic...
.



Relevant Pages

  • Re: continuous function
    ... David C. Ullrich wrote: ... let g:R->R be an arbitrary bijective continous function. ... if fog (the composition of f and g) is alsways continuous for all g's (that ... There's no such thing as fog here. ...
    (sci.math)
  • Re: continuous function
    ... let g:R->R be an arbitrary bijective continous function. ... if fog (the composition of f and g) is alsways continuous for all g's (that ... There's no such thing as fog here. ... David C. Ullrich ...
    (sci.math)
  • Re: continuous function
    ... quasi wrote: ... let g:R->R be an arbitrary bijective continous function. ... if fog (the composition of f and g) is alsways continuous for all g's (that ...
    (sci.math)
  • Re: continuous function
    ... Jonas wrote: ... let g:R->R be an arbitrary bijective continous function. ... if fog (the composition of f and g) is alsways continuous for all g's (that ...
    (sci.math)
  • Re: continuous function
    ... David C. Ullrich wrote: ... let g:R->R be an arbitrary bijective continous function. ... There's no such thing as fog here. ...
    (sci.math)

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