Re: the norm of l^1 isn't derived from scalar product
- From: José Carlos Santos <jcsantos@xxxxxxxx>
- Date: Tue, 23 May 2006 15:17:53 +0100
On 23-05-2006 15:06, eugene wrote:
This is an easy question,
Indeed!
but i'd like to see other approaches, here it is:
Prove that the norm of l^1 isn't derived from scalar product
(sorry, i'm not sure whether it is correct to use exactly this
expression "derived from" in this situation).
I think that the usual expression is "induced from".
Here is what i think:
if it were so, the use Schwartz inequality:
|(x,y)| <= ||x|| * ||y|| and take a pair of vectors
x <> 0, y = 0, then it would have meant that (x,y) = 0 ->
x = y with the contradiction with our choice of x <> 0.
How do you deduce that x = y? Besides, if this argument was correct,
wouldn't it be possible to apply it to the norm of l^2?
Best regards,
Jose Carlos Santos
.
- Follow-Ups:
- References:
- the norm of l^1 isn't derived from scalar product
- From: eugene
- the norm of l^1 isn't derived from scalar product
- Prev by Date: Re: Continuity
- Next by Date: Re: Calculus XOR Probability
- Previous by thread: the norm of l^1 isn't derived from scalar product
- Next by thread: Re: the norm of l^1 isn't derived from scalar product
- Index(es):
Relevant Pages
|