Re: Derivative/Integral of x^x
- From: "G.E. Ivey" <george.ivey@xxxxxxxxxxxxx>
- Date: Mon, 29 May 2006 07:30:41 EDT
What is the derivative/integral of x^x? I know theyThe derivative of x^x is fairly easy: if y= x^x then
exist, b/c my
graphing calculator can calculate them, but what are
the formulas?
Thanks!!!!!
ln(y)= xln(x). The derivative of log(y) with respect to x, by the chain rule, is (1/y)(dy/dx) and the derivative of xln(x), by the product rule, is ln(x)+ x(1/x)= ln(x)+ 1. That is, (1/y)(dy/dx)= ln(x)+ 1 and so dy/dx= y(ln(x)+ 1)= x^x ln(x)+ x^x.
I would be interested in knowing what your calculator gives for the integral of x^x!
.
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