Re: Computing a series



In article <1150737581.157395.140020@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
<csimon@xxxxxxxxxxx> wrote:

I am figthing with a series which doesn't look very complicated but I
can't sort it out.
Here it is:
a[0,0] = 1;
a[m,n] = (n+1)a[m-1,n+1] - a[m-1,n-1]

It's not a series, or even a sequence, because it has two indices.
And you haven't given us enough information to specify it completely.

It turns out that if m+n is even, a[m,n] = 0.

That contradicts your statement a[0,0] = 1.

Robert Israel israel@xxxxxxxxxxxxxxxxx'sInitials.ca
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada

.



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