Re: I don't know why I'm getting the correct answer
- From: "bill" <b92057@xxxxxxxxx>
- Date: 29 Jun 2006 15:04:47 -0700
Pious Audio wrote:
I really appreciate the patience on this board; you all don't know how
much help you are.
Here's the deal, the direction of a problem I'm working on says:
"solve the following equations by the method of forming a new equation
whose roots are "larger" than those of the original equation by
one-half the coefficient of x."
x^2 + 12x + 9 = 0
so I do as ordered:
y = x + 12/2 = x + 6
x = y - 6
(y - 6)^2 + 12 (y - 6) + 9 = 0
+36 - 72 + 9 = - 27; I think.
y^2 = 27
y = (27)^(1/2) y = -(27)^(1/2)
x = (27)^(1/2) - 6 x = -(27)^(1/2) - 6
That's all well-and-good, and the book says that I've produced the
correct answer. However, if I plug the durrived value of x into the
original equation, it doesn't equal zero, it equals 9. What's up?
.
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