Re: random selections of integers from the infinite set of all integers

0 -1 0 1 -2 1 0 1 2 -3 -2 -1 0 1 2 3 -4 -3 -2 -1 0 1 2 3 4...

Every integer appears an infinite number of times in this list. Is it
uncountable?



I am not sure if that is supposed to represent the set of selection results
I am describing, which would contain every one of the infinte number of
integers, each one of which is present an infinite number of times. That is
so because over an infinite amount of time, each integer would be selected
an infinite number of times.

That set, it seems to me, is not a set with just an infinite number of
members (like the set of counting numbers), rather, it is a set with a
membership equal to infinity to the infinity power, or
(infinity)^(infinity).

Is that a countable set?

--
Pete B
http://home.comcast.net/~petebarnes/

<stush@xxxxxxxxxxxxxx> wrote in message
news:1152213117.161740.131780@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Pete B wrote:
Suppose one spends an eternity making perfectly random selections of
integers from the infinite set of all integers.......

[deleted]

.............My contention is that it is a certainty that this selection
process will
eventually select every integer in the set of all integers at least
once, but more likely each integer will be selected an infinite number
of times. I also contend that the infinite set of selected integers
will be an uncountable infinity, since the results are not enumerable
and cannot be placed in one-to-one correspondence with the set of
counting numbers.

0 -1 0 1 -2 1 0 1 2 -3 -2 -1 0 1 2 3 -4 -3 -2 -1 0 1 2 3 4...

Every integer appears an infinite number of times in this list. Is it
uncountable?



.

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