Re: Four Color Theorem


Proginoskes wrote:
bill wrote:
a.khanm@xxxxxxxxx wrote:
bill wrote:
Hypothesis: A simple loopless maximal planar graph with a 5-degree
vertex cannot be a
minimal counter example to the four color theorem!.

It follows from the four colour theorem. However, proving it directly
is another matter. A possible way is induction on the minimum vertex
degree of a maximal planar graph.

Any triangulation with minimum degree 1,2,3 or 4 is cannot be a minimal
counter example by induction on the number of vertices. Assume that
none of the triangulations with minimum vertex degree n-1 is a minimal
counter example and prove the result for n.

This would prove the general version of your statement and the four
colour theorem. But this will take some doing as inductive arguments to
prove four colour theorem and its reformulations have always failed.

My proof is based on the assumption that the following graph is not 4-chroma.
[The drawing below is correct in the "print" mode}

If you're going to post plain text which is supposed to line up, use a
proportional font, like Courier.

|..............| Internal chord
|--------------| External {B-C-B} Kempe chain
D <== A-----B-----C-----B------D ==> A
|--------------|--------------| External {A-C) & {C-D}
Kempe chains

The graph is planar. The {B-C-B} chain may cross the {A-C} & {C-D} chains
at common 'C' vertices.

It looks like you made Kempe's mistake again.

Exactly what was "Kempe's mistake"?

--- Christopher Heckman

.

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