Re: Attempts to Refute Cantor's Uncountability Proof?
- From: Aatu Koskensilta <aatu.koskensilta@xxxxxxxxx>
- Date: Wed, 12 Jul 2006 17:15:39 +0300
Hatto von Aquitanien wrote:
Aatu Koskensilta wrote:
Consider permutations of N - that is, bijections from N to N. A simple
cardinality argument shows that not all of them are recursively
enumerable.
I believe you are talking about something different from what I am talking
about. You seem to be talking about a set of bijections, not a specific
bijection.
Indeed I was. The uncountability of the set of bijections from N to N immediately yields the existence of bijections to N that are not recursively enumerable.
Hatto von Aquitanien wrote:>> N is recursively enumerable. TheIt may be that I need to allow for the domain being a subset of N, but thedefinition of recursive enumerability might as well be - and in someThat would be silly. Where can one find this definition?
instances is given as - a bijection to N.
general form of recursive definition I am familiar with is:
f(1)=c, f(x')=F(x,f(x)), x element of N.
Where x' is the successor of x.
That's the schema of definition by primitive recursion. It's apparent you just don't know what recursive enumerability means - why not take the time to find out?
--
Aatu Koskensilta (aatu.koskensilta@xxxxxxxxx)
"Wovon man nicht sprechen kann, daruber muss man schweigen"
- Ludwig Wittgenstein, Tractatus Logico-Philosophicus
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