Re: calculte probility


matt271829-news@xxxxxxxxxxx wrote:
Bopar wrote:
i have 2 bag of n and m colored balls, can u tell me what is the
probility to pick upa 2 balls of the same color from bag 1 and bag 2 ?

Not unless you (i) specify how many balls of each colour are in each
bag, and (ii) explain the selection procedure (e.g. one ball is chosen
at random from each bag, or whatever it might be).


if i know there are X(=M+N) colors (N colors in bag 1, M in bag 2), any
better chances for me to pick up balls of the same color ?
What is the way to reason this ?

Is this supposed to be a new question or a clarification of the first
question? Whatever, it's impossible to answer without knowing how the
colours are distributed across the two bags, and how the selection is
to be made. Anyway, if there N (different) colours in bag 1, M
(different) colours in bag 2, and M + N (different) colours in total,
then there can't be any ball in bag 1 that is the same colour as any
ball in bag 2. So if you're choosing one ball at random from each bag
then the probability of getting two of the same colour is zero. I
assume this isn't what you meant.

Basically I think you need to explain the problem more clearly.


By the way, yes, it is my homework, I don't have any idea how to solve
it, thanks anyway

Thanks matt,
-----------------------
(1) The colors are repeated, and also there are colors that one bag
does not have but the other does. Picker picks ball up at random with
replacement-return it back to the bag. That's for the first question

-----------------------
(2) The second question is applied to a situation when the number of
colors is known, X or N and M for each bag in this case.
supposing that bag1=color1+color2+....+colorN
bag2=color5+color2+color4+color1+....colorM
color difference =|M-N|.
That's what I meant for the second problem
------------------------
I really don't know how to solve this problem. thanks again

.

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