Re: metric spaces
- From: William Elliot <marsh@xxxxxxxxxxxxxxxxxx>
- Date: Sat, 15 Jul 2006 03:02:47 -0700
On Sat, 15 Jul 2006, William Elliot wrote:
Typo *** corrected at end of this post.
On Sat, 15 Jul 2006, bill wrote:
(X, d) is an arbitrary metric space, and Y = R with d2.
What you mean
with d2?
f : X => R is continuous on X.
Typo, X -> R. I'll consider R to the the reals with the usual
open interval topology.
Can we show that for every c in R, the set {x in X : f(x) > c} is anYes. (c,oo) is an open set and since f is continuous
open set in X?
{ x | c < f(x) } = f^-1((0,oo))
*** { x | c < f(x) } = f^-1((c,oo))
is open..
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