Re: metric spaces



On Sat, 15 Jul 2006, William Elliot wrote:

Typo *** corrected at end of this post.

On Sat, 15 Jul 2006, bill wrote:

(X, d) is an arbitrary metric space, and Y = R with d2.

What you mean
with d2?

f : X => R is continuous on X.

Typo, X -> R. I'll consider R to the the reals with the usual
open interval topology.

Can we show that for every c in R, the set {x in X : f(x) > c} is an
open set in X?

Yes. (c,oo) is an open set and since f is continuous
{ x | c < f(x) } = f^-1((0,oo))

*** { x | c < f(x) } = f^-1((c,oo))

is open.

.



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