Re: Is magnitude more fundamental than the real numbers?

In article <1154979553.224582.269590@xxxxxxxxxxxxxxxxxxxxxxxxxxxx> "Timothy Golden BandTechnology.com" <tttpppggg@xxxxxxxxx> writes:
*** T. Winter wrote:
....
Well, that is already covered in algebra. If a is a zero-divisor in
a ring, so is p.a for all p in that ring. However, the set of zero-
divisors is not necessarily 1-dimensional. For instance in P4, all of
(1, 0, 1, 0), (1, 1, 0, 0) and (0, 0, 1, 1) are zero-divisors, and they
do not span a one-dimensional subset.
....
OK, now I'm catching on. Are you willing to exclude the identity axis?
I'm fairly sure that I can get this arbitrary division to work in P4
for anything other than points on the identity axis, which is a line
passing from +1#1 through the origin and onward through -1*1.

Nope. It will not work with either #1+1, #1*1 and +1-1. Because they
are all three zero-divisors.
--
*** t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, +31205924131
home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~***/
.

Quantcast