Re: square number
- From: "Ioannis" <morpheus@xxxxxxxxxxxx>
- Date: Wed, 16 Aug 2006 01:10:22 +0300
<dcorbit@xxxxxxxxx> wrote in message
news:1155678816.656595.9750@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
[snip]
Here is the solution to a related problem:
Given a number, find what number raised to its own power is equal to
that number.
So given 4, the answer is 2 and given 27 the answer is 3. But what if
you are given 5 or 32.123?
This is known to have a solution via Lambert's W function. The equation x^x=y
is solvable as:
x=log(y)/W(log(y)).
Of course, then one requires an algorithm for the principal branch of W with
good precision, but such algorithms exist and can be found with Google.
--
Ioannis
.
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