Re: Galois groups and tesseract
- From: "secondmouse" <paul.timmons@xxxxxxxxxxxxxx>
- Date: 17 Aug 2006 06:45:09 -0700
Finger trouble - reposting...
The solution appears to be the rather elegant symmetric minimal
polynomial
P[x] = x^8 - x^7 + 2x^6 - 3x^5 + 3x^4 - 3x^3 + 2x^2 - x + 1
(Apols also from the original - I meant the absolute value of the
discriminant)
This contains the quartic subfield defined by Q[y] = y^4 - y - 1
(D=-283).
.
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