Re: analysis exercise,
- From: The World Wide Wade <waderameyxiii@xxxxxxxxxxxxxxxxxxxx>
- Date: Wed, 30 Aug 2006 16:33:43 -0700
In article <0OmJg.9095$cw.5692@fed1read03>,
"vsgdp" <hello@xxxxxxxx> wrote:
Let S and T be nonempty subsets of R with the property that s <= t for all s
in S and all t in T. Prove that sup S <= inf T.
I see this is true from a picture but I could not come up with a direct
proof. I tried supposing sup S > inf T. Then pictorially, there should be
an s in S greater than a t in T to give the contradiction. But I am having
a hard time translating the picture into math symbols.
hint: review the advice you were given on a limsup problem.
.
- References:
- analysis exercise,
- From: vsgdp
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