Re: can anyone tell me the answer related to aliquots

"sandeshavadhani@xxxxxxxxx" <sandeshavadhani@xxxxxxxxx> writes:
can anyone tell me wheather 1/3+1/5+1/7+1/11+1/13+...1/n where n is
either prime or product of primes in the denominator of previous terms
in the series.

Whether it's what? We need a predicate.

Why isn't 1/2 in the series? 2 is prime, you know.

Any number can be neglected.My question is wheather the
sum of the terms of these series can be made exactly one?

I assume that 1/3+1/3+1/3 doesn't count? You don't exclude
it (using the convention that products which may have an
unspecified number of terms may have precisely one term).

Phil
--
"Home taping is killing big business profits. We left this side blank
so you can help." -- Dead Kennedys, written upon the B-side of tapes of
/In God We Trust, Inc./.
.

Relevant Pages

  • Re: can anyone tell me the answer related to aliquots
    ... either prime or product of primes in the denominator of previous terms ... We need a predicate. ... /In God We Trust, Inc./. ...
    (sci.math)
  • Re: can anyone tell me the answer related to aliquots
    ... Phil Carmody wrote: ... either prime or product of primes in the denominator of previous terms ... We need a predicate. ... /In God We Trust, Inc./. ...
    (sci.math)
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