Re: Geometry: No four vectors can be pairwise at an right angle to each other
- From: "Randy Poe" <poespam-trap@xxxxxxxxx>
- Date: 13 Sep 2006 19:57:15 -0700
Hero wrote:
Randy wrote:
...vectors which are orthogonal under the theRandy wrote:
dot product form right angles in the sense in which
Euclid defined them.
There is no such thing as vectors which are orthogonalRandy wrote:
in that sense which do NOT form right angles. Is that
clear enough?
[snip random word salad].I tried my best in giving You an answer.
You wrote a bunch of random gobbledegook and did not comment
on the above.
Do you agree or disagree: There is no such thing as vectors
in R^n which are orthogonal under the dot product and which
do not form right angles.
You seem to have an interpretation of ,,right angle", which is
different from mine.
There are many R^2: a pure number space, a geometric one or... or
consider the change of temperature with time at a certain locality.
This last one is often displayed graphically. Here one has vectors too:
a rise of three degrees in four hours = ( 4 h, 3 d ), this one is in
one graphics at an right angle to a fall of three degrees in the
following 2 hours and 15 minutes = ( 2.25 h, - 3 d). Do You claim, that
there is an right angle between a certain rise in temperature and a
certain fall of temperature?
No. I claim that the GRAPHS of these two lines, which are
geometrical constructs formed of geometrical objects (lines in
a plane) form a right angle, a 90 degree angle in a plane, in
exactly the Euclidean sense.
- Randy
.
- Follow-Ups:
- References:
- Prev by Date: Re: exponent law practice
- Next by Date: Re: Conditional Probability Problem - The Other Child
- Previous by thread: Re: Geometry: No four vectors can be pairwise at an right angle to each other
- Next by thread: Re: Geometry: No four vectors can be pairwise at an right angle to each other
- Index(es):
Relevant Pages
|