Re: JSH: Proving is the easy part

jstevh@xxxxxxx wrote:
It's not at all difficult for me to prove my result showing the
coverage problem of the ring of algebraic integers. Most of the
mathematics after all is just basic algebra.

I can give examples to explain it simply enough for most of you to
understand as that 2 coprime to 6 in evens tells exactly what a
coverage problem looks like.

And the result was published, but then some political stuff got it
yanked and the journal died.

If you were reading about all of this as ancient history, you would be
amazed that any sensible people could ever fight against the result,
and be shocked that denial could last for years.

But this isn't ancient history--it's right now--and for some of you the
truth means you did not get a valid doctorate, or that argument you
thought was a brilliant proof was not, not brilliant, and not a proof.

If you are a professor, you may have the sinking feeling in your gut of
having taught students wrongly for years, even decades.

But what if you just deny, right?

That is the choice that has been made up to this point, so more
students can be taught wrongly, and more people can go through years
with the wrong mathematical ideas.

Proving the mathematics is the easy part. Getting past basic human
denial--people who can't accept not being brilliant, who can't accept
being the wrong ones, and now being closer to crackpots than actual
mathematicians as they refuse to accept, that is what's so hard.


James Harris

So, basically you're saying a degree in math isn't worth anything, right? Then why would so many people get them?

Dave
.

Relevant Pages

  • JSH: Stop being dense
    ... admit the coverage problem with algebraic integers? ... yanking expert status from so many people over that time, and to admit ... others that the algebraic integers did give full coverage, ... Mathematics is crucial for our continued development and "pure math" ...
    (sci.math)
  • JSH Summery #4
    ... the 7 pop up, in only one factor, so that the mathematics clearly shows I'm ... usage of Galois Theory and the theory of ideals. ... where, oddly enough, you are forced to have a ring with fractions!!! ... with the Decker equations, in the ring of algebraic integers, where the goal ...
    (sci.math)
  • Re: Proving is the easy part
    ... coverage problem of the ring of algebraic integers. ... mathematics after all is just basic algebra. ...
    (sci.math)
  • Re: JSH: A simple error
    ... algebraic integers routinely move outside the ring. ... the tautology ... Extreme Mathematics Google group, as is my latest paper which is more ...
    (sci.math)
  • Re: JSH: Stop being dense
    ... admit the coverage problem with algebraic integers? ... yanking expert status from so many people over that time, and to admit ... others that the algebraic integers did give full coverage, ... Mathematics is crucial for our continued development and "pure math" ...
    (sci.math)
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