Re: Round Robin Scheduling



Maury Barbato wrote:

Maury Barbato wrote:

Hello,
I'm trying to solve some problems about round robin

scheduling. Firt of all, some definitions. In a
round
robin tournament each team each other team exactly
one
time. We have 2n teams. The tournament is
organized
in
2n-1 rounds: in a round, each team plays exactly
one

match against another team. Formally, if we denote
by

1,...,2n the teams, then the i-th round,
1<=i<=2n-1,
is the set of all the matches
R_i={{a_1,a_2},...,{a_{2n-1},a_{2n}}},
where a_i is a permutation of {1,...,2n}.
A brilliant algorithm to schedule a Round Robin
tournament is given at the page

http://www.nrich.maths.org/public/viewer.php?
obj_id=1443&part=index&refpage=monthindex.php

(join the two lines to obtain the link).

Now the problems.

(I) Given a round robin tournament R_i,
i=1,...,2n-1,
can you extract a match form ecah round, such that
every team appear at the most two times in the
extracted
matches? Can you find an algorithm to do it?

(II) Consider all the possible round robin
tournaments
you can schedule with 2n teams. How many are
there?






This is a very simple problem: how couldn't I notice

that?! If m=n*(2n-1), then we have m! possible round
robin tournaments.


An unforgivable mistake!! I was quite confused. The
problem is not so simple, as I had initially sensed.



(III) Consider all the possible round robin
tournaments
you can schedule with 2n teams. We say that two of
these
tournaments, R_i and Q_i, are equivalent if there
exist
a permutation s(k) of {1,...,2n} and a permutation
t(k)
of {1,...,2n-1} such that for every 1<=i<=2n-1,
if R_t(i)={{a_1,a_2},...,{a_{2n-1},a_{2n}}},
then
Q_i={{s(a_1),s(a_2)},...,{s(a_{2n-1}),s(a_{2n})}}.
This is an equivalence relation. The problem is:
how
many
equivalence classes are there?

Thank you very much for your attention.
My Best Regards,
Maury

My Best Regards,
Maury

Problems (II) and (III) are quite difficult, I think.
But I'm quite sure that (I) can be solved quite easily,
even if I have no ideas for now.
My Best Regards,
Maury
.



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