Re: nullspaces
- From: Paul Sperry <plsperry@xxxxxxxxx>
- Date: Wed, 27 Sep 2006 18:01:18 GMT
In article <1159364736.591184.155220@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>, boo
<da.perk@xxxxxxxxx> wrote:
It's said that the nullspace basis can be written as the pivot
variables be in terms of the free variables, when reducing them.
However, I have a problem. What happens when you have something like:
I hope you mean what I think you mean>
x1 = 0
x2 = 0
x3 = 0
x4 = 0
in a 4x4 matrix.
Only (0, 0, 0, 0) is a solution - the coefficient matrix is
non-singular.
Also, what about
x1 = 0
x2 = 0
x3 = 0
0 = 0 (for x4)
(0, 0, 0, x) is a solution for every x.
Another one,
x1 = 0
x2 = 0
x3 = x4
0 = 0
(0, 0, x, x) is a solution for every x.
As well as,
0 = 0
0 = 0
0 = 0
0 = 0
(u, v, x, y) is a solution for every u, v, x and y - a rare occasion.
--
Paul Sperry
Columbia, SC (USA)
.
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- nullspaces
- From: boo
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