I have a question regarding eigenvectors. (assume we are working in Cn
- complex set of numbers)
I have seen that if your system (matrix) is hermitian, skew-hermitian
or unitary, the corresponding eigenvectors for your system form a basis
for n-space (assuming your matrix is n x n)
I'm wondering if this result of forming a basis is exclusive to these
three matrix types, or is it possible to have a system that doesn't
have one of the three characteristics listed above, but still form a
basis?
Matrices, Eigenvectors and Eigenvalues ... I have a question regarding eigenvectors.... I have seen that if your system is hermitian,... the corresponding eigenvectors for your system form a basis ... I'm wondering if this result of forming a basis is exclusive to these ... (sci.math)
Re: Matrices, Eigenvectors and Eigenvalues ... I have a question regarding eigenvectors....hermitian, skew-hermitian ... there exists an orthonormal basis of eigenvectors ... But there are normal matrixes which are not the foregoing types ... (sci.math)
Re: Matrices, Eigenvectors and Eigenvalues ... I have a question regarding eigenvectors.... I have seen that if your system is hermitian, skew-hermitian... I'm wondering if this result of forming a basis is exclusive to these ... (sci.math)
Re: Matrices, Eigenvectors and Eigenvalues ... I have a question regarding eigenvectors.... hermitian, skew-hermitian...system form a basis ... I'm wondering if this result of forming a basis is ... (sci.math)
Re: How to identify this kind of equation? ... It's an integro-differential equation....orthonormal basis of L^2[0,infty)), which you then truncate to solve ... orthonormal basis of eigenvectors will exist. ... (sci.math.num-analysis)
