Re: define the division of X/Y


schoenfeld.one@xxxxxxxxx wrote:
Proginoskes wrote:
Mike wrote:
where X and Y are two random variables...

What is the precise and rigorous condition on Y to avoid the "dividing by
zero" problem?

Hmm. Making sure Y is nonzero would do it.

Making the probability that
Y is zero equal to zero might also do it.

That's an insufficient condition.

The probabiltiy of drawing 5 out of the Naturals is 0.

What distribution are you using?

The probability
of drawing a 0.5 out of the set [0,1] is 0. It does not mean that they
cannot ever be drawn.

But things such as the expected value (and moments) can still be
calculated if the probability of dividing by zero is 0.

And I did NOT mean that "probability of event E = 0" is the same as "E
cannot happen". The more precise statement of my intention was: "Y is
nonzero almost everywhere".

--- Christopher Heckman

,
mailx oracle@xxxxxxxxxxxxxx
Subject: Division by Zero

I swear, these humans are getting dumber by the minute ...
--- C
.

.

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