Re: FLTMA: A little group theory
- From: "The Dougster" <DGoncz@xxxxxxx>
- Date: 17 Oct 2006 10:32:41 -0700
The Dougster (I) wrote:
The Dougster (I) wrote:
Hello, all.
Rather than write out the tables for x=7, y=10, and z=13, I computed
them!
http://users.aol.com/DGoncz/Education/NVCC/FLTMA.exe 18 KB
Have some fun with it!
Doug
A new version has been uploaded.
And yet another version generates this text:
X = 3; Y = 4; Z = 5
Phi(3) = 2; Phi(4) = 2; Phi(5) = 4
Inverses: 3 * 3 == 1 mod 4; 4 * 1 == 1 mod 3; 4 * 4 == 1 mod 5; 3 * 2
== 1 mod 5
Quotients: 3 == 4 * 2 mod 5; 4 == 3 * 3 mod 5; 5 == 3 * 3 mod 4; 5 == 4
* 2 mod 3
Orders: 2^2 == -1 mod 5; 3^2 == -1 mod 5; 3^2 == 1 mod 4; 2^2 == 1 mod
3
X = 7; Y = 10; Z = 13
Phi(7) = 6; Phi(10) = 4; Phi(13) = 12
Inverses: 7 * 3 == 1 mod 10; 10 * 5 == 1 mod 7; 10 * 4 == 1 mod 13; 7 *
2 == 1 mod 13
Quotients: 7 == 10 * 2 mod 13; 10 == 7 * 7 mod 13; 13 == 7 * 9 mod 10;
13 == 10 * 2 mod 7
Orders: 2^6 == -1 mod 13; 7^6 == -1 mod 13; 9^2 == 1 mod 10; 2^6 == 1
mod 7
I have proofed this as carefully as I can, but I think there are some
mistakes. I will post the source to:
ftp://users.aol.com/DGoncz/Education/NVCC
Doug
.
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