3^m/2^n -> r ?
- From: Han de Bruijn <Han.deBruijn@xxxxxxxxxxxxxx>
- Date: Wed, 18 Oct 2006 11:07:20 +0200
Given an arbitrary positive real number (r).
Can somebody prove that there exist natural numbers (m) and (n)
such that r is approximated with arbitrary accuracy by 3^m/2^n ?
Han de Bruijn
.
- Follow-Ups:
- Re: 3^m/2^n -> r ?
- From: The Last Danish Pastry
- Re: 3^m/2^n -> r ?
- From: A N Niel
- Re: 3^m/2^n -> r ?
- From: José Carlos Santos
- Re: 3^m/2^n -> r ?
- From: victor_meldrew_666
- Re: 3^m/2^n -> r ?
- Prev by Date: Re: taylor series for tanh(x)
- Next by Date: Re: They fail in reply to me all the time
- Previous by thread: Fitting a parabola segment, or similar, to two points, one with a given slope
- Next by thread: Re: 3^m/2^n -> r ?
- Index(es):
