Re: FLTMA: A little group theory

There is a probem with FLTMA1.exe, at
ftp://users.aol.com/DGoncz/Education/NVCC.

I compute a quotient, then take the power. It doesn't work out.

I call the quotients qxiyz for quotient of x divided by y mod z,
qyixz similarly, and so qzixy and qxiyx. I call the inverse y mod z
iyz, and so
ixz, ixy, and iyx.

I find (x * iyz)^n mod z =/= qxiyz^n mod z

I was confused about how Chip Eastham got to (x/y)^n == -1 mod z but it
seemed right, and I think I understand it now, but working out y * iyz
= 1 mod z to solve for iyz, and computing qxiyz = (x * iyz) mod z
before looking at the powers qxiyz^n mod z just doesn't seem to work.

Have I made one too many substitutions and lost the validity of the
modular arithmetic?

Most likely it's a typo but I am not seeing it.

The latest version has been uploaded.

Doug

.

Relevant Pages

  • Re: FLTMA: A little group theory
    ... I compute a quotient, then take the power. ... n is a multiple of the order of in Z/xZ* ... Something very close to that, if m divides n, which I think I've seen ...
    (sci.math)
  • Re: FLTMA: A little group theory
    ... I compute a quotient, then take the power. ... order does not give a power of 4 equal to -1 in Z/15Z. ... n is a multiple of the order of in Z/xZ* ...
    (sci.math)