eigenvector
- From: "jennifer" <scrilla_12_1999@xxxxxxxxx>
- Date: 27 Oct 2006 21:34:16 -0700
Suppose T is in L(V) is such that every vector in V is am eigenvector
of T.Prove that T is a scalar multiple of the identity operator.
Proof:- Assume T is in L(V), let T be in V.
Then Tv= Lv for all v in V and Lambda in F
where F is a field
Tv= LIv where I is the identity map.
This is where i am stuck, where do i go from here please?
.
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