compact sets 2,
- From: vsgdp <nospam@xxxxxxxxx>
- Date: Thu, 02 Nov 2006 19:45:28 EST
Is my argument rigorous enough:
Prove the intersection of an arbitrary collection of compact subset of metric space M is compact.
Let B be the intersection of all the compact subsets.
Let (p_n) be a sequence in B. Then (p_n) is a sequence in each subset A in the intersection. But since every A compact, (p_n) has an accumulation point, say p, in every A. So p in B. Now the book doesn't prove it, but it gives a reference that compact set S in a metric space is equivalent to every sequence in S having an accumulation point in S. So by this fact, we can conclude B is compact.
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