can it be a distrubution function?



Hi,
this week's HW had this distribution function

f =
1-(3/4)exp(-x) x >= 0
0 otherwise

then I was asked to compute P(0 <= x <= 2). if i understand correctly,
i need to compute the integral of f(x) at the given interval. as a
preliminary stage i tried to compute the integral of f on the entire
sample space. i expected it to be 1. what i got was:

(integral)[0,+inf](1-(3/4)exp(-x)) = (x + (3/4)exp(-x)) between 0 and
+inf = inf !

this integral does not converge, because of the "x". so, am i doing
something wrong or that f cannot be a distribution function ?

thanks

.



Relevant Pages

  • mean of continuous random variable makes no sense
    ... of ffrom -inf to +inf is 1 and fis nonnegative), ... the area under the curve to the left of m is supposed to be ... produce the value m which divides the curve into two equal areas. ... Then fis a distribution function, but the integral of x*ffrom - ...
    (sci.math)
  • Re: Transforming bound space
    ... distribution function for any probability distribution. ... Any rational function the degree of whose denominator ... exceeds that of its numerator and whose denominator has no real zeroes ... +inf. ...
    (sci.math)
  • Re: mean of continuous random variable makes no sense
    ... of ffrom -inf to +inf is 1 and fis nonnegative), ... the area under the curve to the left of m is supposed to be ... Furthermore, the function is called a density function, not a distribution function. ... Math Tutor on the Internet and in Central New Jersey and Manhattan ...
    (sci.math)
  • Re: can it be a distrubution function?
    ... tamiry wrote: ... if f is the distribution function? ... +inf = inf! ... the integral has to be 1 if f is a DENSITY function. ...
    (sci.math)

Quantcast