An infinite debate
- From: "Ajeet" <asgrewal@xxxxxxxxx>
- Date: 7 Nov 2006 02:57:47 -0800
Hi All,
Consider the following set :
S = U S_i (0<=i<infinity and U denotes the set operation of union)
where S_i is the set of all numbers, whose decimal representations are
of length i. For example the number 3.4 belongs to S_2. (assume the
decimal does not add to the length, so 34 would also belong to S_2).
Argument : S = R (set of all real numbers)
========
Proof:
=====
Suppose a real number "r" does not exist in S. let the decimal
representation of "r" be d_0.d_1d_2d_3......(to infinity) where d_i is
the ith digit.
+Since r does not belong to S, there will be some digit k which will be
off. More precisely
the prefix d_0.d_1d_2d_3....d_k-1 belongs to S but,
the prefix d_0.d_1d_2d_3....d_k-1d_k does not belong to S
But this is not possible because that prefix would have been added in
all sets S_j where j >= k+1.
Therefore no such k exists.
Therefore r belongs to S.
Counter - Proof:
=============
Consider the real sqrt(2). The decimal representation of this real
would be infinite.
Now all the sets in the union are disjoint. Therefore there must exist
a set S_m which contains sqrt(2) and no other set can contain this
number.
However, no such m can exist, because then m would need to be infinite.
(there is no natural number "infinity")
Hence S cannot be R.
Paradox anyone?
Ajeet
.
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