Re: counter example in analysis



In article <4553626D.2020807@xxxxxxxxxxxxxxxxxxx>,
Eckard Blumschein <blumschein@xxxxxxxxxxxxxxxxxxx> wrote:

On 11/8/2006 9:24 PM, Virgil wrote:

As Q cannot be resolved into single points isolated from their neighbors
any more than R can, Eckard is delusional again.

Here the widespread idea of Q seems to include R.

Not in any standard mathematics, but only Eckie can speak for what goes
on in his personal form of mathematics.


Rationals are always a
set of single numbers.

Any set is a set of single members,

Then there is no set that corresponds to the continuum of reals.

Except the set of reals.

A continuum is something every part of which has parts.

The the reals do not form a continuum in that sense of the word.

if one ignores the ordering. The
rationals are just as dense as the reals when one contemplates their
order properties.

... which are hypothetized out of the exhaustion of what cannot be
exhausted.

Eckards mental capacities long have been if he thinks that has any
mathematical meaning.

Sorry, no more time for today.
.



Relevant Pages

  • Re: counter example in analysis
    ... Eckard Blumschein wrote: ... phantasm like omega) to the rationals. ... What model of reals does EB propose in which reals are ... large that member may be as a set. ...
    (sci.math)
  • Re: counter example in analysis
    ... The set of reals cannot be so "resolved", but then neither can the set ... of rationals, nor any other densely ordered set. ... Eckard is delusional again. ... actually dense with absolutely no intervals in between the fictitious ...
    (sci.math)
  • Re: Courage?
    ... > In a separate post, you posed the question of whether pi was a quantity, ... To say that the reals are not "really" ... Eckard ... Prev by Date: ...
    (sci.math)
  • Re: .999... ?= 1
    ... > mathematics has failed for centuries to satisfactory resolve the issue, ... >> do with the continuum defined in math. ... Sure, Eckard, that's a very deep problem of set theory: ...
    (sci.math)

Quantcast