Re: Another Conditional Probability Question
- From: David Marcus <DavidMarcus@xxxxxxxxxxxxxx>
- Date: Thu, 9 Nov 2006 23:06:48 -0500
Mad_man_on_a_MissIon wrote:
C6L1V@xxxxxxx wrote:
Mad_man_on_a_MissIon wrote:
C6L1V@xxxxxxx wrote:
Mad_man_on_a_MissIon wrote:
A hospital uses 2 tests to classify blood. Every blood sample is
subjected to both tests. The first test correctly identifies blood
type with probability .7, and the second test with probability .8. The
probability that at least one of the tests correctly identifies the
blood type is .9.
Well, you are given P(E), P(F) and P(E or F). Can you see how to use
this info to get P(E & F)? Don't you recall a formula involving these
things?
R.G. Vickson
I was figuring the statement "The probability that at least one of the
tests correctly indentifies the blood type is .9." would be something
like Pr(E ^ F) U Pr(E U F)
What do you mean by the union of two probabilities (or do you mean
"maximum")?
instead of Pr(E U F)
Normally, the statement "at least one of E, F" means exactly {E union
F} = {E or F}, and that was my assumption. Anyway, what is the context?
Is it a homework problem? If so, go with the prof's/textbook's
definitions.
I typed the exact problem as is. As far as unions go according to the
book, (professor is quite absent minded, but i'm going to ask her
tomorrow anyways) Pr(E or F) as in
Pr(E U F) means one or the other, it has no specification as to whether
this means just "one or the other", or as in boolean logic, OR, or XOR.
Does Pr(E 'union' F) mean Pr(E OR F) or
Pr(E XOR F)? This book has been quite ambiguous on several occasions,
if you ask me KSU should throw it out.
E union F is E or F (not xor). The original problem said "at least one
of", so that is certainly the union of the two events.
--
David Marcus
.
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