Re: Cantor Confusion

Franziska Neugebauer wrote:
mueckenh@xxxxxxxxxxxxxxxxx wrote:

David Marcus schrieb:

I see. But recently you used the word "completed infinity".
I don't think I ever said that. Do you have a quote?
Here it is:
In the below post, I was just trying to paraphrase what you are
saying.
Please don't try to paraphrase what I said, because I don't believe
that you understand it sufficiently.

This is due to your conceptional weakness.

[...]

I didn't say I would say that or that I understood what you were
trying to say.
The question was whether you "ever said that" it. I hope this
question as been settled now.

In fact, I don't know what you you mean by the phrase. Did you
really misunderstand what I wrote?
There is no misunderstanding possible. You refuted Lester's
interpretation, by proposing to have a better one:

"That doesn't seem to be what WM is saying. He seems to be saying that
the notion of a completed infinity leads to either absurdities or
contradictions. Perhaps he thinks the way to avoid these absurdities
is to only consider things that can be physically produced."

I [k]now that cranks never admit having made an error.

Introspection?

But do you think that obvious lies like this are a way to reach your
aim?>

I cannot spot any lie.

I don't know what you mean by "completed anywhere".
The completed initial segment contains every natural number.

http://mathworld.wolfram.com/InitialSegment.html

A "completed initial segment" is not an *initial* segment.

Another segment contains not every natural number.

No *initial* segment contains every element of its underlying set.

F. N.

How exactly d you define "initial segment"? It would seem to me to be a subset of an ordered set which, if it contains element x, also contains every element with an index in the ordered set which is less than x's. If this is the definition, then the complete set IS an initial segment of itself. If you disagree with thi definition, can you provide a better one?

Tony
.

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