Re: Maximise polynomial degree N
- From: "Chip Eastham" <hardmath@xxxxxxxxx>
- Date: 19 Nov 2006 06:18:06 -0800
marmitage@xxxxxxxxx wrote:
I'd like find a,b and n to maximise the following polynomial:
1 + b + (a-b) b^n + (b-1-a) b^n a^(N-n)
where 0 < a < b < 1
and N > 4 is fixed
(n and N are integers)
Ideally I'd like to show that n*>(N/2)
or that for a given division of N into m and N-m then it is optimal to
set n = max(m, N-m) if a and b are optimal also.
I've solved fully numerically but analytically have sunk a lot of time
into it and not got anywhere. If anyone can help, or explain to me why
an analytical solution is evading me, I'd be very grateful.
In a variety of ways, such as taking special case a = b,
although strictly speaking your inequality a < b doesn't
allow this, we obtain the simpler optimization problem:
F(x) = 1 + x - x^N for x in (0,1) [x = a = b]
An analytic solution can be obtained for the maximum
at x = N^(-1/(N-1)), and this independent of the choice
of n. I suspect that this is the answer, but I have not
analyzed it satisfactorily yet.
regards, chip
.
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