Re: tensor product twister
- From: "magya_bloom@xxxxxxxxx" <magya_bloom@xxxxxxxxx>
- Date: 23 Nov 2006 09:49:34 -0800
magya_bloom@xxxxxxxxx wrote:
Jannick Asmus wrote:
On 23.11.2006 14:59, magya_bloom@xxxxxxxxx wrote:
not sure what "inverse image of the natural ring homomorphism" means in
this context.
Sorry for being not very clear. I meant "preimage": If f: G -> H is a
map of sets, then the preimage of a subset H' of H is f^-1(H') = { g in
G | f(g) in H' }.
I understood that part. I just don't know what that subset H' is. When
you say preimage of a natural homomorphism, which sub-algebra of A*B
are we pulling back?
of course we are pulling back M. Sorry about my stupid question. But
why do we need nullstellensatz to conclude that m1 is maximal?
.
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