How to solve for L?
- From: "bluelabel" <bluelabel.invalid@xxxxxxxx>
- Date: Sat, 25 Nov 2006 18:21:39 +0100
hello, I have the following system of 3 equations:
2x
1 + L(--------------- + 1) = 0
1+(x^2+y^2-2)
2y
-1 + L(--------------- - 1) = 0
1+(x^2+y^2-2)
arctg (x^2 + y^2 -2) = 2-x+y
The only thing I know for sure is that solving for L leads to the value
L=-1/3, giving (x,y)=(1,-1). But despite my many attempts I did not find a
way to determine L.
Could you show me how to do that?
Thank you.
PS.
The equations system arises from the problem of determining the critical
points of the function f(x,y) = x-y with the condition arctg(x^2+y^2-2) =
2-x+y, applying Lagrange's multipliers method.
.
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