Re: Need help calculating overall network reliability
- From: William Elliot <marsh@xxxxxxxxxxxxxxxxxx>
- Date: Sun, 3 Dec 2006 01:20:56 -0800
On Sun, 3 Dec 2006, hyperbp wrote:
Ok this diagram was composed with a monospaced font, I am not sure that
this will display correctly, because HTML eats spaces for lunch:
|-C-| |-E-|
| | | |
INPUT--A--B------| |----| |------- OUTPUT
| | | | | |
| |-D-| |-F-| |
| |
|-------------G-------------------|
It appeared correctly in monospace font.
A workaround for html is to shut it off.
Web based forums don't allow that, thus need for ... instead of spaces.
Newsgroups, and email that is not written with html,
allow clustering of more than one space.
Sorry, I can be of no further help on your network problem
other than to assist you with posting ascii graphics and art.
.I need to calculate the overall network reliabilityif the individual node reliabilities are:
G=0.98
A=0.95, B=0.97, C=0.92, D=0.94, E=0.90, F=0.88,
subsystems C and D is:
I believe that I done that with the following steps
The reliability of the redundant network including
RCD = RC + RD - (RC)*( RD) = 0.92 + 0.94 -(0.92)(0.94) = 0.9952
subsystems E and F is:
The reliability of the redundant network including
REF = RE + RF - (RE)*( RF) = 0.90 + 0.88 -(0.90)(0.88) = 0.988
(0.95)(0.97)(0.9952)(0.988) = 0.906072
The reliability of the path is:
RABCDEF = (RA)*(RB)*(RCD)*(REF) =
+ 0.98 - (0.906072)(0.98) = 0.998121
The reliability of the combined network is:
RSYSTEM = RABCDEF + RG - (RABCDEF)(RG) = 0.906072
how the overall network reliability changes if node G
The part that I am having trouble understanding is
is standby-redundant, how do I calculate that? After
searching the web for awhile I found a website that
gave me this formula to use: 1-(P(A)*P(B | A')). Is
that correct, and how to I apply it?
Thanks for your help
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- Re: Need help calculating overall network reliability
- From: William Elliot
- Re: Need help calculating overall network reliability
- From: hyperbp
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