Re: 0^0: "Solving a 1200-year-old problem"
- From: impartially_insane@xxxxxxxxxxx
- Date: 6 Dec 2006 22:25:08 -0800
impartially_ins...@xxxxxxxxxxx wrote:
Black.Wyvern.11@xxxxxxxxx wrote:
His first two rules are true.
However, I deduced this from a reciprocal triangle.
.....1...
------------
..0...|....Infinity
But nullity? This is rubbish.
0//0 is 1 or Infinity, depending on how you analyze the problem.
0/0 can take on any value you want. Consider lim x->0 ax/x for any real
a.
A.
I guess you could argue that this is just a(0/0), which would give 0/0
= 1. There's other forms you can take that will also produce 0/0
though, but not 1 or infty. lim x-> 0 (e^{ax}-1)/x will also go to a.
A.
His pseudomaths is rubbish. Someone shun this man immediately!
.
- References:
- 0^0: "Solving a 1200-year-old problem"
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- Re: 0^0: "Solving a 1200-year-old problem"
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- Re: 0^0: "Solving a 1200-year-old problem"
- From: Black . Wyvern . 11
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