Re: 4x4 matrices using Cramer's Rule
- From: Virgil <virgil@xxxxxxxxxxx>
- Date: Mon, 11 Dec 2006 15:49:12 -0700
In article <a1658$457d265b$82a1e228$31541@xxxxxxxxxxxxxxxx>,
Han de Bruijn <Han.deBruijn@xxxxxxxxxxxxxx> wrote:
Uinseann wrote:
Anyone got any ideas on how to solve 4x4 matrices by using Cramer's
Rule. I've looked in a multitude of math books and surfed the web for
hours to no avail. I can do a 3x3 no problem but unfortunately I dont
seem to be able to see how to do a 4X4. Any advice that anyone might
be able to offer regarding the problem below would be greatly
appreciated.
13 10 0 0 i1 6
-10 13 0 -3 X i2 = 10
0 0 18 -3 i3 0
0 -3 -3 6 i4 5
The following is in Delphi Pascal. I hope it's so much readable that you
can translate it into you own favorite programming language. The outcome
is, iff I've made no mistakes:
-2.38532110091743E-0001 = i1
9.10091743119266E-0001 = i2
2.34250764525994E-0001 = i3
1.40550458715596E+0000 = i4
Or det(M) = 24525 and
i1 = -5850/24525 = -26/109
i2 = 22320/24525 = 496/545
i3 = 5745/24525 = 383/1635
i4 = 34470/24525 = 766/545
Is there any particular reason why you need to use Cramer's rule?
There are much better methods.
.
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