Re: Cantor Confusion
- From: Virgil <virgil@xxxxxxxxxxx>
- Date: Tue, 12 Dec 2006 13:06:54 -0700
In article <457ece72@xxxxxxxxxxxxxxxxxxx>,
Tony Orlow <tony@xxxxxxxxxxxxx> wrote:
*** T. Winter wrote:
In article <457d8cc0$1@xxxxxxxxxxxxxxxxxxx> Tony Orlow <tony@xxxxxxxxxxxxx>
writes:
> *** T. Winter wrote:
> > In article <1165761763.908889.34550@xxxxxxxxxxxxxxxxxxxxxxxxxxx>
> > Han.deBruijn@xxxxxxxxxxxxxx writes:
> > ...
> > > Let P(a) be the probability that an arbitrary natural is divisible
> > > by
> > > a fixed natural a. Then P(a) = 1/a . Forbidden by set theory.
> >
> > No. Not specifically forbidden by set theory. Forbidden because there
> > are
> > no appropriate definitions for the words you are using (they are not
> > used
> > conforming to standard definitions, so you better supply definitions).
> > In probability theory (as is commonly use) you have to define how you
> > *select* your arbitrary natural. You have not done so, so probability
> > theory does not have an answer.
>
> Why does that matter?
It does matter because if you do not properly define your problem,
mathematics is not able to give an answer.
It's sufficiently defined if one assumes that there is a uniform
probability distribution.
From which assumption, added to the others, one can deduce that 0 = 1,and all sorts of peculiar things.
> This is the same thing as your stupid ball and
> vase trick. Why do you need to label anything, or know what you're
> choosing from the infinite set?
Because that is part of the problem setting. Giving that setten will
allow mathematics to model the question and give an answer.
That problem has a clear answer with or without the labels: the sum
diverges as f(n)=9n. The labels are confounding, not clarifying.
What is confounding to TO is clairifying to anyone with the wits to
understand it. The result depends on the labeling. Eliminating the
labeling makes the result impossible to determine.
And it is bad to think that because for a sequence of sets holds that
lim{n -> oo} |S_n| = k
with some particular value of k, that also
| lim{n -> oo} S_n | = k
because the latter statement contains something that has not been
defined in mathematics.
I'm not sure what that statement is supposed to say. Can uoi give an
example?
But even when we define it, it is not certain
that it holds. Given the following (I think reasonable) definition:So, what, S_n is supposed to be an initial segment of the sequence?
lim{n -> oo} S_n = S
if:In (2), it sounds like a would not exist in ANY S_n if it's not in S.
(1) for every element a in S there is an n0 such that a is in each of
the sets S_n with n > n0
(2) for every element a not in S there is an n0 such that a is not in
each of the sets S_n with n > n0.
So from some particular point an element either remains in the sets in
the sequence or remains out of the sets.
You mean, at some point you can tell whether a given element a is in S,
because if it were, it would be there by then?
Okay that interval degenerates to 0....
With this definition (when we look at the rationals) we have that
lim{n -> oo} [0, 1/n] = [0]
and so:
lim{n -> oo} | [0, 1/n] | = aleph0 != 1 = | lim{n -> oo} [0, 1/n] |
(I am talking standard mathematics here).
Are the |'s supposed to denote set size? If so, how can you claim that
[0,0] contains aleph_0 elements?
So taking cardinality and limits can not be interchanged except in some
particular cases. But that is not unprecedented in mathematics.
limits and integrals can also not be interchanged except in particular
cases. And so can the interchange is not in general passoble if one
of the things you interchange is a limit. Even interchanging limits
is not in general possible. Consider:
lim{x -> oo} lim{y -> oo} (2x + 3y)/xy
True, but is it relevant?
Yup!
TO claims certain changes in order of operations make no difference.
Here it is shown that such changes in order of operations can and often
do make significant differences.
So that TO must PROVE that his changes of order don't make a difference
before he can claim they don't.
.
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