Re: Cantor Confusion

In article <1166090594.020341.42340@xxxxxxxxxxxxxxxxxxxxxxxxxxx>,
mueckenh@xxxxxxxxxxxxxxxxx wrote:

I do not understand why you argue that in
lim{x -> oo} lim{y -> oo} (2x + 3y)/xy = 0 = lim{y -> oo} lim{x -> oo}
(2x + 3y)/xy
interchanging limits is not possible.

Regards, WM


Nor do I.

But for lim{x -> oo} lim{y -> oo} (2x + 3y)/(x + y) = 3
and lim{y -> oo} lim{x -> oo} (2x + 3y)/(x + y) = 2,
one cannot exchange the order of the limits without changing the value
of the result.
.