Re: ZFC in 4 Axioms.
- From: "MoeBlee" <jazzmobe@xxxxxxxxxxx>
- Date: 14 Dec 2006 15:21:02 -0800
zuhair wrote:
Definition:
Ax(x is P_embeded <-> (Ay: y e x <-> P(y)) /\ P(x))
What does 'P' range over? Formulas? If so, then I'm concerned whether
we can justify your definition even as a definitional schema. But let's
see what we find.
But first, please use parentheses rather than the ':' colon symbol. It
will be much clearer.
Now, I don't know whether you want:
x is P_embedded
stands for
Ay(yex <-> (P(y) & P(x)))
or
x is P_embedded
stands for
Ay(yex <-> P(y)) & P(x)
or
x is P_embeddd
stands for
Ay yex <-> (P(y) & P(x))
or
x is P_embdded
stands for
(Ay yex <-> P(y)) & P(x)
MoeBlee
.
- Follow-Ups:
- Re: ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- References:
- ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- From: hagman
- Re: ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- From: hagman
- Re: ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- From: hagman
- Re: ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- From: MoeBlee
- Re: ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- From: MoeBlee
- Re: ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- From: MoeBlee
- Re: ZFC in 4 Axioms.
- From: zuhair
- Re: ZFC in 4 Axioms.
- From: MoeBlee
- Re: ZFC in 4 Axioms.
- From: zuhair
- ZFC in 4 Axioms.
- Prev by Date: Re: Cantor Confusion
- Next by Date: Re: Cantor Confusion
- Previous by thread: Re: ZFC in 4 Axioms.
- Next by thread: Re: ZFC in 4 Axioms.
- Index(es):