Re: A misapplication of probability theory in exam grading
- From: israel@xxxxxxxxxxx (Robert Israel)
- Date: 15 Dec 2006 19:08:22 GMT
In article <1166205811.228936.105840@xxxxxxxxxxxxxxxxxxxxxxxxxxx>,
<jankrihau@xxxxxxxxxxx> wrote:
pauldepstein@xxxxxxx wrote:
In standardized multiple-choice exams, where each question has 5ordinary policy
options, a common (and extremely dumb) rule used is that correct
answers score 4 but wrong answers score -1.
Presumably the inventors of this rule noticed that the
of simply counting the right answers produces a randomnessfactor, and
they desired to eliminate it by "penalizing random guessing"according
to the above scheme.the exams
The irony is that this penalty clause does absolutely nothing to
penalize random guessing because a random guess scores 0 on average,
the same as an omitted question.
Therefore, from a game theory stance, an optimal way to play
is to attempt all questions regardless of whether or not there is agrading system
penalty clause.
Therefore, when played correctly, the randomness components in both
grading systems is exactly the same.
The inventors of the modified grading system saw a problem, and very
bizarrely managed to "solve" the problem by changing the
to one with exactly the same problem.assuming -1 for a
If the intent is to "penalize random guessing" then,
wrong answer (and 5 choices per question), the amount for a correctuniversally
answer needs to be < 4, not exactly 4.
How did such a mathematically dumb grading system become so
accepted? And what on earth is the rationale for the (-1,4) grading
system, as opposed to (for example) (-1, 3)?
Paul Epstein
Hi,
I don't think it was an attempt to remove randomness, but rather to
arrange so that random guessing doesn't score better than not
answering. Hence the choice of (-1, 4): It gives the expected value 0
for random guessing. Although there is still an element of randomness,
the expected score for the whole test becomes 4 x the number of
questions the candidate actually knew the answer to, regardless of
whether he or she made random guesses or chose to leave some questions
unanswered.
In addition, you want to don't want to unduly discourage a
student who is not completely sure of the answer but has
enough knowledge or skill to see that some answers are more
likely to be correct than others. A poor student who isn't
certain of the answers has an interesting optimization
problem to solve. Suppose there are n questions, and I have
probability p of getting any question right. How many should
I answer to maximize my probability of passing the test?
Robert Israel israel@xxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
.
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