Re: Irrational numbers questions
- From: Dave Seaman <dseaman@xxxxxxxxxxxx>
- Date: Wed, 3 Jan 2007 13:52:38 +0000 (UTC)
On Wed, 03 Jan 2007 08:09:15 -0500, G. A. Edgar wrote:
Can it be proven that, with e irrational, also e^N (with N natural) is
irrational? Guess so, but why ..
Let's see ... If a = sqrt(2), then a is irrational, but a^2 is rational.
But e is also transcendental, and from that we can conclude that e^n is
transcendental for each natural number n.
--
Dave Seaman
U.S. Court of Appeals to review three issues
concerning case of Mumia Abu-Jamal.
<http://www.mumia2000.org/>
.
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