Re: closed bounded in Banach space
- From: "Sauro" <sauromalventi@xxxxxxxx>
- Date: 4 Jan 2007 10:32:34 -0800
José Carlos Santos ha scritto:
Sauro wrote:
Is a closed bounded subset of a Banach space also compact?No. Take the closed unit ball in any infinite-dimensional
Banach space. It is closed and bounded, but not compact.
Is a closed subset S of a Banach space also compact (I assume such a S
is a subset of a finite dimensional subspace of our Banach space)?
If your question is "is every closed subset of every finite-demensional
subspace of a Banach space compact?" then the answer is "yes".
Best regards,
Jose Carlos Santos
Excuse me Carlos, but, thinking more closely to my question "is every
closed subset of every finite-demensional subspace of a Banach space
compact?", it doesen't seem to be true, consider for example the set
{(x,y) in |R^2 such that x lies in [0,1] and y lies in [0, + infty ) }.
Then such a set is a closed subset of |R^2, which itself is a
finite-demensional subspace of a Banach space, |R^2. On the other hand
{(x,y) in |R^2 such that x lies in [0,1] and y lies in [0, + infty ) }
is cleary not compact...
What do you think about?
Regards, S.
.
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