Re: location of foci in ellipse




The Last Danish Pastry wrote:
<conrad@xxxxxxxxxx> wrote in message
news:1168067893.314253.275640@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

The following explanation I don't quite follow:

http://mathforum.org/library/drmath/view/55323.html

The part that I don't follow is their conclusion
that d(Y1, F1) = d(Y2, F2) = a/2

Specifically how they determiend that it is
a divided by 2!

I know they will evaluate to the same value
but why divide by two? What piece of information
tells us that this is so?

We have shown that d(X1,F1)+d(X1,F2) = a
So, d(Y1,F1)+d(Y1,F2) = a

What is there to suggest that d(Y1,F1) + d(Y1,F2)
is true? I don't see how it follows from the observation
that d(X1, F1) + d(X1, F2) = a.

But, d(Y1,F1) = d(Y1,F2)
So, 2*d(Y1,F1) = a
Thus, d(Y1,F1) = a/2


--
conrad

.



Relevant Pages

  • location of foci in ellipse
    ... The following explanation I don't quite follow: ... Specifically how they determiend that it is ... but why divide by two? ...
    (sci.math)
  • Re: location of foci in ellipse
    ... but why divide by two? ... a represents the constant that is the sum of their distance ... then a/2 will give us the radii and therefore ...
    (sci.math)
  • Re: location of foci in ellipse
    ... Specifically how they determiend that it is ... but why divide by two? ... "Let a be the length of the major axis." ... Clive Tooth ...
    (sci.math)
  • Re: location of foci in ellipse
    ... Specifically how they determiend that it is ... but why divide by two? ... This is a well known property of the ellipse. ... Clive Tooth ...
    (sci.math)
  • Re: location of foci in ellipse
    ... conrad@xxxxxxxxxx schrieb: ... Specifically how they determiend that it is ... but why divide by two? ... right hand side.(Actually P is not marked,sum distance 2a need not be ...
    (sci.math)

Quantcast