Re: Cantor Confusion

mueckenh@xxxxxxxxxxxxxxxxx wrote:
There is a union of paths for every path.
There is a union of trees yielding the infinite tree.
Every finite tree reaches from the root to a level n.
The union contains every level which is a natural number.

Every node which is placed on a finite level (= every digit with a
finite index) is in the union of all finite trees. Therefore every path
containing nodes on a finite level (= every sequence of digits at
places with finite indexes) is in the union of finite trees. There is
nothing remaining!

Consider the path in the infinite tree that always goes left. Which
finite tree is this in?

--
David Marcus
.

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