Re: number with (-1)^0 = ?
- From: "Pubkeybreaker" <Robert_silverman@xxxxxxxxxxxx>
- Date: 16 Jan 2007 05:53:05 -0800
mina_world wrote:
Hello sir~
I believe the x^0 = 1 for x >= 0.(including 0^0 = 1).
Mathematics is not done by "belief"
The restriction x >= 0 isn't necessary.
and then What is (-1)^0 ?
Trivially it is 1. Let N be a natural number. Then (-1)^N/(-1)^N =
(-1)^(N-N) = -1^0 = 1
.
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